The angle between the pair of lines whose equation is 4x2+10xy+my2+5x+10y=0 is
tan−1(3/8)
tan−1(3/4)
tan−1{225−4m/(m+4)}, m∈R
None of these
Being a pair of lines, abc+2fgh−af2−bg2−ch2=0.This gives m=4, now, find the angles between the lines