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The angle between the pair of lines $x^{2} + 4 xy + 2 y^{2} = 0$ is

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sin−1317

cos−1317

sin−1317

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Correct option is B

If θ is acute angle between pair of lines represented by the equation ax2+2hxy+by2=0 then cosθ=a+b(a−b)2+(2h)2For the equation x2+4xy+2y2=0, a=1,2h=4,b=2Hence, cosθ=31+16=317Therefore,θ=cos−1317

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The angle between the pair of lines x2+4xy+2y2=0 is

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The angle between the pair of lines $x^{2} + 4 xy + 2 y^{2} = 0$ is