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The angle between the pair of lines $x^{2} - 2 xysecα + y^{2} = 0$ is

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Correct option is C

If θ is acute angle between pair of lines represented by the equation ax2+2hxy+by2=0then cosθ=a+b(a−b)2+(2h)2For the equation x2−2xysecα+y2=0,a=1,2h=−2secα,b=1 Hence, cosθ=20+4sec2α=22secα=cosαTherefore, θ=α

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The angle between the pair of lines x2−2xysecα+y2=0 is

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The angle between the pair of lines $x^{2} - 2 xysecα + y^{2} = 0$ is