The angle between the parabolas  y2=4ax  and  x2 = 4ay at their point of  intersection other than the origin.

Pt of intersection of y2=4ax&x2=4ay are (0,0) (4a,4a)2ydydx=4a⇒dydx=2aym1=dydx(4a,4a)=2a4a=12m2=(4a,4a)=2x4a=8a4a=2tan⁡θ=2−121+1=34                            tanθ  =  34   ⇒θ = tan−1(34)