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The angle between the parabolas  y2=4ax  and  x2=4ay at their point of  intersection other than the origin.

a
π2
b
π6
c
tan−1(34)  =  θ
d
tan θ =  43

detailed solution

Correct option is C

Pt of intersection of y2=4ax&x2=4ay are (0,0) (4a,4a)2ydydx=4a⇒dydx=2aym1=dydx(4a,4a)=2a4a=12m2=(4a,4a)=2x4a=8a4a=2tan⁡θ=2−121+1=34                            tanθ  =  34   ⇒θ = tan−1(34)

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