Q.
The angle between the parabolas y2=4ax and x2 = 4ay at their point of intersection other than the origin.
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a
π2
b
π6
c
tan−1(34) = θ
d
tan θ = 43
answer is C.
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Detailed Solution
Pt of intersection of y2=4ax&x2=4ay are (0,0) (4a,4a)2ydydx=4a⇒dydx=2aym1=dydx(4a,4a)=2a4a=12m2=(4a,4a)=2x4a=8a4a=2tanθ=2−121+1=34 tanθ = 34 ⇒θ = tan−1(34)
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