Angle between the two planes of which one plane is 4x+y+3z=0 and another plane containing the lines x−32=y−23=z−13,x−23=y−32=z−23 is
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a
π3
b
π2
c
π6
d
2π3
answer is B.
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Detailed Solution
Angle between the planes cosθ=a1a2+b1b2+c1c2∑a12∑a22Equation of the plane containing the lines x−32=y−23=z−13,x−23=y−32=z−23 is x−3y−2z−1233323=0⇒3x−3+3y−2−5z−1=0⇒3x+3y−5z−10=0∴cosθ=12+3−152222=0⇒θ=π2