The angle of elevation of a jet plane from a point A on the ground is 600 . After a flight of 20 seconds at the speed of 432 km/hour, the angle of elevation changes to 300. If the jet plane is flying at a constant height, then its height is

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36003m

12003m

18003m

24003m

answer is B.

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Detailed Solution

BE is height of where the jet flying ED = Distance travelled by Jet in 20 seconds=432×518×20=2400 meters tan⁡60∘=hABAB=h3tan⁡30∘=hh3+240013=hh3+2400h3+2400=h3h3−h3=24002h3=2400h=12003m

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