The angle of elevation of an object from a point P on the level ground is α . Moving d meters on the ground towards the object, the angle of elevation is found to be β . Then the height (in meters) of the object is

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d.tanα

d.cotβ

dcot α+cot β

dcot α−cot β

answer is D.

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Detailed Solution

tanα=hx+d⇒x+d=hcotαtanβ=hx⇒x=hcotβ∴ x+d−x=h[cotα−cotβ]⇒h=dcotα−cotβ

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