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The angle of intersection of the circles $x^{2} + y^{2} = 4$ and $x^{2} + y^{2} = 2 x + 2 y$ , is

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Correct option is D

We know that the angle of intersection of two circles of radii r1 and r2 is given bycos⁡θ=r12+r22−d22r1r2,where d is the distance between their centresHere, r1=2,r2=2 and d=2.∴ cos⁡θ=4+2−22×2×2=12⇒θ=π4

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The angle of intersection of the circles x2+y2=4 and x2+y2=2x+2y, is

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The angle of intersection of the circles $x^{2} + y^{2} = 4$ and $x^{2} + y^{2} = 2 x + 2 y$ , is