The angle which the normal to the line x – 3 y + 8 = 0 passing through the origin, makes with the positive x-axis is
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a
30°
b
60°
c
120°
d
150
answer is C.
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Detailed Solution
We write the equation of the given line in the normal form as −12x+32y=82or xcosα+ysinα=p, where cosα=−12, sinα=32 and p=4,α being the required angle ⇒α=120∘