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Questions  

In any ABC, the value of ab2+c2cosA+bc2+a2cosB+ca2+b2cosC=

a
3abc2
b
3a2bc
c
3abc
d
3ab2c

detailed solution

Correct option is C

We have,ab2+c2cos⁡A+bc2+a2cos⁡B+ca2+b2cos⁡C=ab(bcos⁡A+acos⁡B)+bc(ccos⁡B+bcos⁡C)+ca(ccos⁡A+acos⁡C)=abc+abc+abc=3abc

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