In any ∆ABC, the value of ab2+c2cosA+bc2+a2cosB+ca2+b2cosC=
3abc2
3a2bc
3abc
3ab2c
We have,
ab2+c2cosA+bc2+a2cosB+ca2+b2cosC=ab(bcosA+acosB)+bc(ccosB+bcosC)+ca(ccosA+acosC)=abc+abc+abc=3abc