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Questions  

For any complex number z, the minimum value of |z|+|z2i| is

a
0
b
1
c
2
d
none of these

detailed solution

Correct option is C

We have, for z ∈ C|2i|=|z+(2i−z)|≤|z|+|2i−z|⇒ 2≤|z|+|z−2i|Thus, minimum value of |z|+|z−2i| is 2 and it it attained when z = i.

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