Q.
For any complex number z, the minimum value of |z|+|z−2i| is
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a
0
b
1
c
2
d
none of these
answer is C.
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Detailed Solution
We have, for z∈C|2i|=|z+(2i−z)|≤|z|+|2i−z|⇒2≤|z|+|z−2i|Thus, minimum value of |z|+|z−2i| is 2 and it is attained when z =i.
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