The area bounded by the curves y=x2−2x+2;x≥1 and its inverse is given by

y=x−12+1Put y=xx=x2−2x+2x2−3x+2=0x−1x−2=0x=1,2Required  area =2∫12x−x−12−1dx=2x22−x−133−x12=22−13−2−12+1=21−56=216=13