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 The area bounded by the curves y=x22x+2;x1 and its inverse is given by 

 

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By Expert Faculty of Sri Chaitanya
a
13
b
23
c
53
d
43
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detailed solution

Correct option is A

y=x−12+1Put y=xx=x2−2x+2x2−3x+2=0x−1x−2=0x=1,2Required  area =2∫12x−x−12−1dx=2x22−x−133−x12=22−13−2−12+1=21−56=216=13


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