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a
103
b
173
c
203
d
253
answer is D.
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Detailed Solution
The given lines are ±2x-3±3y+4=5The area of parallelogram formed by lines :2x+3y−4=0, 2x−3y−12=0 2x+3y+6=0, 2x−3y−2=0 is = 6--412-22-3-23= 253 Area of parallelogram formed by the lines a1x+b1y+c1=0 ,a1x+b1y+c2=0 a2x+b2y+d1=0 , a2x+b2y+d2=0 is c1-c2d1-d2a1b2-a2b1