$\text{ The area enclosed by the curves }x{y}^2=a^2(a-x)cnd(a-x)y^2=a^{2}x\text{ is }\lambda a^2\text{ sq. units, }$$\text{ where }\lambda =\underset{¯}{(\text{ Assume }\pi =3.14)}$

$The area of the required region is 4{\int }_0^{\frac{a}{2}}a\sqrt{\frac{a-x}{x}}dx$

$substittue x=a{\sin }^2\theta$

$The definite integral value is 4\left(\frac{\mathrm{\pi }}{4}-\frac{1}{2}\right)=\mathrm{\pi }-2=1.14$