Q.

The area of a parallelogram formed by the lines ax±by±c=0 is

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a

c2/ab

b

2c2/ab

c

c2/2ab

d

none of these

answer is B.

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Detailed Solution

The given lines are ax±by±c=0 or x± c/a+y± c/b=1The vertices of rhombus are are Ac/a,0,   C−c/a, 0, B0, c/b, D0, −c/b. Therefore the diagonal AC and BD of quadrilateral ABCD are perpendicular. Hence, it is a rhombus whose area is given by 12×AC×BD=12×2ca×2cb=2c2ab
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