First slide
Equation of line in Straight lines
Question

The area of a parallelogram formed by the lines ax±by±c=0 is 

Moderate
Solution

The given lines are ax±by±c=0

 or x±c/a+y±c/b=1

The vertices of rhombus are are Ac/a,0,   Cc/a,0B0,c/b,D0,c/b. Therefore the diagonal AC and BD of quadrilateral ABCD are perpendicular. Hence, it is a rhombus whose area is given by 

12×AC×BD=12×2ca×2cb=2c2ab 

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