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Questions  

The area of the parallelogram formed by the lines  2x3y+a=0,3x2ya=0,2x3y+3a=0 and 3x2y2a=0 in square unit is 

a
a25
b
2a25
c
3a25
d
none of these

detailed solution

Correct option is B

Let A be the required area. Then, A=(3a−a){−2a−(−a)}2    −33    −2=2a25 sq. units

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