First slide

Cartesian plane

Question

The area of the parallelogram formed by the lines $2 x - 3 y + a = 0, 3 x - 2 y - a = 0, 2 x - 3 y + 3 a = 0$ and $3 x - 2 y - 2 a = 0$ in square unit is

Moderate

A

$\frac{a^{2}}{5}$
B

$\frac{2 a^{2}}{5}$
C

$\frac{3 a^{2}}{5}$
D

none of these

Solution

Let A be the required area. Then,
$A = |\frac{(3 a - a) {- 2 a - (- a)}}{|\begin{array}{ll} 2 - 3 \\ 3 - 2 \end{array}|}| = \frac{2 a^{2}}{5}$ sq. units

Get Instant Solutions

When in doubt download our app. Now available Google Play Store- Doubts App

Recieve an sms with download link

Doubts App

OR

SCAN ME

Doubts App

Doubts App