The area of the parallelogram formed by the lines y=mx , y=mx+1,y=nx, and y=nx+1 equals
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a
|m+n|/(m−n)2
b
2/|m+n|
c
1/(|m+n|)
d
1/(|m−n|)
answer is D.
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Detailed Solution
y - mx is a line through (0, 0) andy - mx+ 1 is a line Parallel to y - mx having y-intercePt 1 . The vertices are O(0, 0), X' A(ll(m - n), ml(m - n)). The areaof parallelogram is given by2×Ar(ΔOAB)=2×120010111m−nmm−n1=1|m−n|