Area of quadrilateral formed by the lines 4y−3x−a=0 , 3y−4x+a=0,4y−3x−3a=0 and 3y−4x+2a=0 is
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a
a25
b
a27
c
2a27
d
2a29
answer is C.
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Detailed Solution
The area of the parallelogram formed by the lines a1x+b1y+c1=0a2x+b2y+d1=0a1x+b1y+c2=0,a2x+b2y+d2=0 is c1−c2d1−d2a1b2−a2b1 sq. units. ∴ Required area =(2a)(a)(4)(−4)−(3)(−3)=2a27