The area of the quadrilateral formed by the tangents from the point (2, -1) to the circle x2+y2+4x−8y−5=0 with a pair of radii joining the points of contact of these tangents is

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answer is B.

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Detailed Solution

Area = rS11 r=5,pt=(2,−1) =54+1+8+8−5 =516 = 20

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