The area of the quadrilateral whose vertices are (1,2),(6,2),(5,3) and (3,4), is
32 sq. units
112 sq. units
12 sq. units
none of these
We have,
Δ1=121 62 2=−5,Δ2=126 52 3=4
Δ3=125 33 4=112 and, Δ4=123 14 2=1
Area of quadrilateral =−5+4+112+1=112 sq. units