The area of the region, enclosed by the circle $$x2+y2=2$$ which is not common to the region bounded by the parabola $$y2=x$$ and the straight line y $$=$$ x, is:

Question

The area of the region, enclosed by the circle  $$x2+y2=2$$ which is not common to the region bounded by the parabola $$y2=x$$ and the straight line y $$=$$ x, is:

Infinity Learn · Accepted Answer

The requireed area is  the area of the region bounded by the circle minus the area of the region bounded by $$y2=x$$ and the line $$y=xRequired$$ area $$=Total$$ area – enclosed area $$=$$  $$2$$π−∫$$01x$$−xdx                                                                    $$=2$$π−$$2x3/23$$−$$x2201$$                                                                    $$=2$$π−$$23$$−$$12$$ $$=2$$π−$$16$$ $$=12$$π−$$16$$

The area of the region, enclosed by the circle $x^{2} + y^{2} = 2$ which is not common to the region bounded by the parabola $y^{2} = x$ and the straight line y = x, is:

Remember concepts with our Masterclasses.

Ready to Test Your Skills?

free study material

The area of the region, enclosed by the circle x2+y2=2 which is not common to the region bounded by the parabola y2=x and the straight line y = x, is:

Remember concepts with our Masterclasses.

Ready to Test Your Skills?

free study material

The area of the region, enclosed by the circle $x^{2} + y^{2} = 2$ which is not common to the region bounded by the parabola $y^{2} = x$ and the straight line y = x, is: