Area of the regular hexagon whose diagonal joins (2, 4) and (6, 7) is

We have A(2,4) and 8(6,7) as end points of diagonal of the hexagon. ∴ AB=5So, length of the line segment joining centre of the hexagon and one of the vertices is 52∴ Area of hexagon =6× Area of equilateral triangle having  side length 32=6×34×254=7538