The area (in sq. units) of the part of the circle x2+y2=36,which is outside the parabola y2=9x,is:

see full answer

High-Paying Jobs That Even AI Can’t Replace — Through JEE/NEET

🎯 Hear from the experts why preparing for JEE/NEET today sets you up for future-proof, high-income careers tomorrow.

An Intiative by Sri Chaitanya

24π+33

12π+33

12π−33

24π−33

answer is D.

(Unlock A.I Detailed Solution for FREE)

Detailed Solution

The circle and curve intersect at x=3∴Area =πr2−2∫039xdx+∫3636−x2dx =36π−123−2x236−x2+18sin−1x636 =36π−123−29π−932+3π =24π−33

Watch 3-min video & get full concept clarity