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The area of the triangle on the argand diagram formed by the complex number z, iz and z+iz

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a

|z|2

b

|z|22

c

|z|23

d

z2

answer is B.

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Detailed Solution

Let z=x+iy. Then iz=-y+ix and z+iz=x-y+ix+y∴Area = 12x-yx-yxyxx+yy =12x2+y2 =12z2

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