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The area of the triangle formed by (k,k),(k+1, k+1),(k+2k,k) is

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a

k3

b

2k

c

1

d

2

answer is C.

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Detailed Solution

A(k,k),B(k+1,k+1),C(k+2,k) Area of ΔABC=12|−1−1−20|=12(2)=1

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