Area of the triangle formed by the line x+y=3 and the angle bisectors of the pairs of straight x2−y2+2y=1 is
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a
2sq. units
b
4sq. units
c
6sq. units
d
8sq. units
answer is A.
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Detailed Solution
x2−y2+2y=1 or x=±(y−1)The bisectors of the above lines are x=0 and y=1So, the area between x=0,y=1, and x+y=3 is the shaded region shown in the figure. The area is given by (1/2)×2×2=2sq.units