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Questions  

The area of the triangle formed by the lines x2+3xy+y2=0,x+y+1=0 is 

a
−25
b
52
c
-52
d
25

detailed solution

Correct option is B

The area of the triangle formed by the lines ax2+2hxy+by2=0and lx+my+n=0 is n2h2−abam2−2hlm+bl2For the equations x2+3xy+y2=0,x+y+1=0The values are a=1,2h=3,b=1,l=1,m=1,n=1Therefore, the area of the triangle is  AA=12322−11112−311+112  =541  =52Therefore, the area of the triangle is 52

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