The area of the triangle formed by the lines y=ax, x+y−a=0, and the y-axis is equal to

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121+a

a21+a

12a1+a

a221+a

answer is D.

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Detailed Solution

B≡0,a,A1≡a1+a,a21+aΔOA1B=12OBA1M=12aa1+a=12a21+a

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