The area of the triangle formed by the lines y=x, y=0 and x=sin−1a4+1+cos−1⁡a4+1−tan−1⁡a4+1 is sq. units, where k =

We observe that  a4+1≥1 for all a∈R Therefore x=sin−1⁡a4+1+cos−1⁡a4+1−tan−1⁡a4+1 is meaning it for a= 0 and in that case it becomes y=π4. Thus, the given lines y=x,y=0 and x=π4 These lines form a right triangle area π232 sq. umts