The area of the triangle formed by the points (k, 2 – 2k), (– k + 1, 2k) and (– 4 – k, 6 – 2 k) is 70 units. For
four real values of k
no integral value of k
two integral values of k
only one integral value of k
k2−2k1−k+12k1−4−k6−2k1=140
which is true for only one integral value of k.