The area of a triangle is 5 sq. units. Two of its vertices are (2,1) and (3,−2) . The third vertex lying on y=x+3. The coordinates of the third vertex are given by
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a
(34,−34),(74,132)
b
(14,12),(34,32)
c
(−23,23),(72,32)
d
(−32,32),(72,132)
answer is D.
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Detailed Solution
As the vertex lies on the line y=x+3 its coordinates are of the form (x,x+3), The area of the triangle those vertices are (2,1),(3,−2) and (x,x+3), is |12|2113−21xx+31||=12|4x−4|=|2x−2| Accordingly to the given coordinates 2x−2=±5 ⇒ x=−32,72 .Thus the coordinates of the third vertex can be (−32,32),(72,132) .