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Q.

The area of a triangle is 5 square unit. Two of its vertices are (2,1),(3,−2) and the third vertex lies on the line y=x+3 . The third vertex can be

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a

(7/2,13/2)

b

(3/2,3/2)

c

(7/2,−13/2)

d

(3/2,−3/2)

answer is A.

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Detailed Solution

Conceptual ( substituting the options in the given line)Alternative methodLet (h,k) be the third vertex It lies on y=x+3  ⇒k=h+3 Area of triangle=5 122113-21hk1=5 2(-2-k)-1(3-h)+1(3k+2h)=10 3h+k=17 substituting k=h+3 3h+h+3=17 4h=14 h=72  hence k=132
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