The area of the triangle whose vertices are the points represented by the complex number z, iz and zi+z is

Area of the triangle is given byΔ=14zz¯1iz−iz¯1z+izz¯−iz¯1Applying R3→R3−R1−R2 we getΔ=14zz¯1iz−iz¯100−1=14(−1)zz¯iz−iz¯∣=14|(−1)(i)zz¯|111−1=14|z|2(2)=12|z|2