The area of the triangle whose vertices are the points represented by the complex number z, iz and zi+z is
14|z|2
18|z|2
12|z|2
12|z|
Area of the triangle is given by
Δ=14zz¯1iz−iz¯1z+izz¯−iz¯1
Applying R3→R3−R1−R2 we get
Δ=14zz¯1iz−iz¯100−1=14(−1)zz¯iz−iz¯∣=14|(−1)(i)zz¯|111−1=14|z|2(2)=12|z|2