Q.

Area of a triangle with vertices given by z, iz z + iz, where z is a complex number, is

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a

0

b

12|z|2

c

|z|2

d

2|z|2

answer is B.

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Detailed Solution

Area of triangle isΔ=14||zz¯1iz−iz¯1z+izz¯−iz¯1∣Using R3→R3−R1−R2 we getΔ=14||z    z¯    1iz    −iz¯    10    0    −1∣=14|−izz¯−izz¯|=12|z|2
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Area of a triangle with vertices given by z, iz z + iz, where z is a complex number, is