In the Argand plane, the vector z=4−3i is turned in the clockwise sense through 1800 and stretched three times. The complex number represented by the new vector is:
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a
12+9i
b
12−9i
c
−12−9i
d
−12+9i
answer is D.
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Detailed Solution
|z|=42+(−3)2=5 Let z1 be the new vector obtained by rotating z in the clockwise sense through 1800 , therefore, z1=e−iπz=(cosπ−isinπ)z , i.e., z1=−4+3iThe unit vector in the direction of z1=−4+3i ,is -45+i35Therefore, required vector =3|z|(−45+35i)=15(−45+35i)=−12+9i