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Q.

In the Argand plane, the vector z=4−3i  is turned in the clockwise sense through 1800  and  stretched three times. The complex number represented by the new vector is:

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a

12+9i

b

12−9i

c

−12−9i

d

−12+9i

answer is D.

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Detailed Solution

|z|=42+(−3)2=5 Let z1  be the new vector obtained by rotating z  in the clockwise sense through 1800 , therefore,    z1=e−iπz=(cosπ−isinπ)z , i.e., z1=−4+3iThe unit vector in the direction of z1=−4+3i ,is -45+i35Therefore, required vector      =3|z|(−45+35i)=15(−45+35i)=−12+9i
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