Q.

The arithmetic mean of  nC0,nC1,…,nCn, is

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a

1n

b

2nn

c

2n−1n

d

2n+1n

answer is B.

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Detailed Solution

Clearly, Required mean = nC0+nC1+…+nCnn=2nn
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The arithmetic mean of  nC0,nC1,…,nCn, is