Arrange the following limits in the ascending order. 1) Limx→0tan4x−sin4xx6 2) Limx→0tan8x−sin8xx5tanx5 3) Limx→0tan3x−sin3xxsin4x 4) Limx→0tan5x−sin5xx2.sinh3x.tan2x

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1,2,3,4

3,1,4,2

1,2,4,3

2,1,3,4

answer is B.

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Detailed Solution

Limx→0tannax−sinnaxxn+2=n2an+2

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