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Q.

Arrange the following limits in the ascending order.                                                                                                            1) Limx→0tan4x−sin4xx6    2) Limx→0tan8x−sin8xx5tanx5   3) Limx→0tan3x−sin3xxsin4x  4) Limx→0tan5x−sin5xx2.sinh3x.tan2x

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a

1,2,3,4

b

3,1,4,2

c

1,2,4,3

d

2,1,3,4

answer is B.

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Detailed Solution

Limx→0tannax−sinnaxxn+2=n2an+2
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Get ₹ 1 crore* worth scholarship for JEE / NEET / Foundation
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Arrange the following limits in the ascending order.                                                                                                            1) Limx→0tan4x−sin4xx6    2) Limx→0tan8x−sin8xx5tanx5   3) Limx→0tan3x−sin3xxsin4x  4) Limx→0tan5x−sin5xx2.sinh3x.tan2x