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The average of n numbers x1,x2,x3,,xn is M. If xn is replaced by x', then new average is

a
M−xn+x′
b
nM−xn+x′n
c
(n−1)M+x′n
d
M−xn+x′n

detailed solution

Correct option is B

M=x1+x2+x3……xnn⇒ nM=x1+x2+x3+…+xn−1+xn⇒ nM−xn=x1+x2+x3+…+xn−1⇒ nM−xn+x′=x1+x2+x3+…+xn−1+x′⇒ nM−xn+x′n=x1+x2+x3+…+xn−1+x′n∴ New average=nM−xn+x′n

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