First slide
Hyperbola in conic sections
Question

A and B are foci of hyperbola 25(x1)2+(y+1)2=k2(3x+4y+5)2,k>1 and P is a  variable point on hyperbola such that APB is right angled isosceles triangle. If 

k=tanα,α[0,2π] and sum of all values of α is 2b (where a and b are co-prime numbers), then

Difficult
Solution

 When AP=2a+2aeAP2=AB2+PB24a2+a2e2+8a2e=4a2e2+4a2e2e22e1=0e=2+222 or 2222 reject e=1±2k=1+2α=6712 and 24712

 Sum of all values =7π4a=7 and b=2

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