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Theorems of probability

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Question

A and B are two candidates seeking admission in IIT. The probability that A is selected is 0.5 and the probability that both A and B are selected is at most 0.3.The probability of B getting selected cannot exceed.

NA
Solution

 Given P(A)=0.5 and P(AB)0.3
 

 we have P(AB)=P(A)+P(B)-P(AB)1

P(A)+P(B)1+P(AB)1+0.3=1.3

0.5+P(B)1.3P(B)0.8

Thus probability of B getting selected cannot exceed 0.8

 

 

 


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