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An Intiative by Sri Chaitanya
a
a→ ⋅ b→|a→|2 a→ − b→
b
a→ ⋅ b→|b→|2 b→ − a→
c
b→ × (a→ × b→)|b→|2
d
a→ ⋅ b→|a→|2 a→ + b→
answer is A.
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