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a
a→ ⋅ b→|a→|2 a→ − b→
b
a→ ⋅ b→|b→|2 b→ − a→
c
b→ × (a→ × b→)|b→|2
d
a→ ⋅ b→|a→|2 a→ + b→
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Correct option is A
The altitude required is BN→BN→=ON→−OB→= projection of OB→ on ON→−b→= (b→ ⋅ a∧) a∧ − b→= b→ ⋅ a→|a→| a→|a→| − b→ = (b→ ⋅a→) a→|a→|2 − b→Similar Questions
The vector equation of the plane through the point and to the line of intersection of the plane and is
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