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An Intiative by Sri Chaitanya
a
P(A/B)>P(B)>P(A∩B)
b
P(A/B)>P(A∩B)>P(B)
c
P(B)>P(A/B)>P(A∩B)
d
P(A∩B)>P(A/B)>P(B)
answer is A.
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