Q.

a→ and b→  are two unit vectors that are mutually perpendicular. A unit vector that is equally inclined to a→,b→ and a→×b→ is

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a

12(a→+b→+a→×b→)

b

12(a→×b→+a→+b→)

c

13(a→+b→+a→×b→)

d

13(a→+b→+a→×b→)

answer is C.

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Detailed Solution

Let the required vector r→ be such that r→=x1a→+x2b→+x3a→×b→We must have r→⋅a→=r→⋅b→=r→⋅(a→×b→)  (as r→,a→,b→ and a→×b→ are unit vectors and r→ is equally inclined to  a→,b→ and a→×b→)now  r→⋅a→=x1,r→⋅b→=x2,r→⋅(a→×b→)=x3⇒r→=λ(a→+b→+(a→×b→))also,  r→⋅r→=1⇒λ2(a→+b→+a→×b→)⋅(a→+b→+(a→×b→))=1or  λ2|a→|2+|b→|2+|a→×b→|2=1or  λ2=13or λ=±13⇒ r→=±13(a→+b→+a→×b→)
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