Q.

a→ and b→ are two vectors, such that a→⋅b→<0 and |a→⋅b→|=|a→×b→|  then the angle between  vectors a→ and b→ is

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a

π

b

7π4

c

π4

d

3π4

answer is D.

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Detailed Solution

|a→⋅b→|=|a→×b→|⇒ |a→||b→||cos⁡θ|=|a→||b→||sin⁡θ|  (where θ is the angle between a→ and b→)⇒ ∣cos⁡θ|=|sin⁡θ∣⇒ θ=π4 or 3π4( as 0≤θ≤π) But a→⋅b→<0, therefore θ=3π4
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a→ and b→ are two vectors, such that a→⋅b→<0 and |a→⋅b→|=|a→×b→|  then the angle between  vectors a→ and b→ is