Q.
a→ and b→ are two vectors, such that a→⋅b→<0 and |a→⋅b→|=|a→×b→| then the angle between vectors a→ and b→ is
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a
π
b
7π4
c
π4
d
3π4
answer is D.
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Detailed Solution
|a→⋅b→|=|a→×b→|⇒ |a→||b→||cosθ|=|a→||b→||sinθ| (where θ is the angle between a→ and b→)⇒ ∣cosθ|=|sinθ∣⇒ θ=π4 or 3π4( as 0≤θ≤π) But a→⋅b→<0, therefore θ=3π4
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