A(a→),B(b→) and C(c→) are the vertices of triangle ABC and R(r→) i, any point in the plane of triangle ABC, the r→⋅(a→×b→+b→×c→+c→×a→) i,is always equal to
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a
zero
b
[a→b→c→]
c
-[a→b→c→]
d
none of these
answer is B.
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Detailed Solution
A vector perpendicular to the plane of A(a→),B(b→) and C(c→)(b→−a→)×(c→−a→)=a→×b→+b→×c→+c→×a→Now for any point R(r→) in the plane of A, B and C is (r→−a→)⋅(a→×b→+b→×c→+c→×a→)=0r→⋅(a→×b→+b→×c→+c→×a→) −a→⋅(a→×b→+b→×c→+c→×a→)=0r→⋅(a→×b→+b→×c→+c→×a→)=0→+a→⋅b→×c→+0→r→⋅(a→×b→+b→×c→+c→×a→)=[a→b→c→]