A, B, C are the angles in a triangle cotA,cotB,cotC are the roots of x3−λ1x2+λ2x−λ3=0 then
λ2=0
λ2=1
λ3=-1
λ3=1
In ΔABC, cotAcotB+cotBcotC+cotCcotB=1 ∵A+B+C=π⇒λ2=1