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A, B, C are the angles in a triangle $\cot A, \cot B, \cot C$ are the roots of $x^{3} - λ_{1} x^{2} + λ_{2} x - λ_{3} = 0$ then

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λ2=0

λ2=1

λ3=-1

λ3=1

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detailed solution

Correct option is B

In ΔABC, cotAcotB+cotBcotC+cotCcotB=1 ∵A+B+C=π⇒λ2=1

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A, B, C are the angles in a triangle cotA,cotB,cotC are the roots of x3−λ1x2+λ2x−λ3=0 then

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A, B, C are the angles in a triangle $\cot A, \cot B, \cot C$ are the roots of $x^{3} - λ_{1} x^{2} + λ_{2} x - λ_{3} = 0$ then