A, B, C are the sets of letters needed to spellthe words STUDENT, PROGRESS and CONGRUENT,respectively. Then n(A∪(B∩C)) is equal to
8
9
10
11
A={D,E,N,S,T,U]B={E,G,O,P,R,S}C={C,E,G,N,O,R,T,U}
So A∪(B∩C)={D,E,N,S,T,U}∪{E,G,O,R}={D,E,G,O,N,R,S,T,U}
and n[(A∪(B∩C)]=9