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A, B, C are three sets such that n(A) = 25,n(B)=20,n(c)=27,n(A∩B)=5,n(B∩C)=7 and A∩C=∅ then n(A∪B∪C) is equal to

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a

60

b

65

c

67

d

72

answer is A.

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Detailed Solution

A ∩ C=ϕ⇒A∩B∩C=ϕ.∴n(A∪B∪C)=n(A)+n(B)+n(C)−n(A∩B)−n(B∩C) −n(A∩C)+n(A∩B∩C)= 25+20+27−5−7−0+0=60.

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