a→,b→ and c→  are three vectors of   equal magnitude. The angle between each pair of vectors is π3 such that  |a→+b→+c→|=6 . then a→=

|a→+b→+c→|2=6 or  |a→|2+|b→|2+|c→|2 +2(a→⋅b→+b→⋅c→+c→⋅a→)=6⇒ |a→|=|b→|=|c→| and  a→⋅b→=|a→||b→|⋅cos⁡π3 i.e., a→⋅b→=12|a→|2∴ 3|a→|2+3|a→|2=6⇒ |a→|2 or |a→|=1